In its most elementary form, a transformer consist of two coils wound of wire and inductively coupled to each other. When alternating (AC) current at a given frequency flows in either coil, an alternating voltage of the same frequency is induced in the other coil. The value of this voltage depends on the degree of coupling and the flux linkages in the two coils. The coil connected to a source of alternating voltage is usually called the primary coil, and the voltage across this coil is the primary voltage. Voltage induced in the secondary coil maybe be greater than or less than the primary voltage, depending on the ratio of the primary to secondary turns. A transformer is termed a stepup or a stepdown transformer accordingly.
Name Plate Rating (Voltage Ratio):
The voltage ratio of the transformer is specified as V1 (rated)/V2 (rated). It means that when voltage V1 (rated) is applied to the primary winding, the secondary winding voltage on full load at specified power factor is V2 (rated). The ratio V1 (rated)/V2 (rated) is not exactly equal to NI/N2, because of voltage drops in the primary and secondary. These drops being small are neglected and it is assumed that for all practical purposes
The rating of the transformer is specified in units of VA/ kVA/ MVA depending upon its size.
kVA(rated) =V(rated) x I(fullload) / 1000
Transformer Losses:
The transformer has no moving parts so that its efficiency is much higher than that of rotating machines. The various losses in a transformer are enumerated below:
CoreLoss: These are hysteresis and eddycurrent losses resulting from alternations of magnetic flux in the core. It is emphasized that the coreloss is constant for a transformer operated at constant voltage and frequency as are all power frequency transformers.
Copperloss (I2Rloss): This loss occurs in winding resistances when the transformer carries the load current; varies as the square of the loading expressed as a ratio of the fullload.
Load (stray) loss: It largely results from leakage fields inducing eddycurrents in the transformer walls, and conductors.
Dielectricloss: The source of this loss is in the insulating materials, particularly in solid insulation.
The major losses are by far the first two: Pi the constant core (iron)loss and PCu the variable copperloss. It will be easily seen in the following sections that transformer losses and the parameters of its equivalent circuit can be easily determined by two simple tests without actually loading it.
TRANSFORMER TESTING
Two major difficulties which do not warrant the testing of large transformers by direct load test are:
(i) Large amount of energy has to be wasted in such a test.
(ii) It is impossible for large transformer to arrange a load large enough for direct loading.
Thus performance characteristics of a transformer must be computed from a knowledge of its equivalent circuit parameters which, in turns, are determined by conducting simple tests involving very little power consumption, called nonloading tests.
In these tests the power consumption is simply that which is needed to supply the losses incurred. The two nonloading tests are the opencircuit (OC) test and shortcircuit (SC) test. In both these tests voltage, current and power are measured from which the resistance and reactance of the input impedance can be found. Thus only four parameters can be determined which correspond to the approximate equivalent circuit of Fig.1.

Open Circuit Test
The purpose of this test is to determine the shunt branch parameter of the equivalent electrical circuit of transformer.
 Connect the Unit under Test (UUT, the transformer) low voltage side to the supply rated ac voltage
 Keep the high voltage side opencircuited
 Connect power ananlyzer or power meter between the AC supply and the UUT.
 At no load (Open circuit) condition, the no load current (Io) should be small around 26% of the rated current.
 Since Io is small, so it safe to assume V1 equal to E1 by neglecting the series impedance. Thus for all practical purposes, the power input on noload equals the core (iron) loss.
⦁ The circuit parameters can be computed from three reading at different operating points
Yo = Gi –jBm
Yo = Io/V1
Gi =Po/(V1)2
Bm = sqrt (Yo^2 – Gi^2)
⦁ Thus the OC test yields the core –loss and the parameter of the shunt branch of the equivalent circuit.
Short Circuit Test
The series parameters of the transformer as well as its copper losses could be evaluated using the short circuit test.
Transformer resistances and leakage reactance are very small, the input voltage to circulate the rated load current under short circuit is as low as 58% of the rated voltage ( in most transformers)
 Raise the input supply voltage gradually from zero till the transformer draws fullload current.
 The power analyzer gives the reading as under:
Voltage =Vsc ; Current = Isc; Power input =Psc.
 Since at low voltages, transformer iron losses can be neglected thus only copper losses of the transformer can be obtained.
Psc =Pc(copperloss)
Z= Vsc/Isc=sqrt(R^2+ X^2)
R= Psc/(Isc^2)
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